Thank you very much, you helped a lot.
One last question please -
According to the paper you sent, windowing is needed on the impulse response to isolate the IR for each harmonic. How did you choose the initial window size?
Thank you John.
1. I am sorry for the confusion, here is another example:
H = [84.8190 43.6400 34.9430 34.1940 38.1570 31.1410]; (Fundamental, H2, H3.. H6 in SPL)
Can you please share the formula you used to calculate the THD (REW result: 0.513% for the calculation with 6 harmonics)...
Thank you for the answer,
I gave an example of a calculation using 2 harmonics only to understand the formula and still can't figure it out.
I Would appreciate help-
Does the algorithm consider the energy at the harmonic frequency only or also at frequencies around it?
How is the division...
Hello,
I would appreciate an explanation of the THD calculation
For example: for 2 harmonics only, I get the values:
H1 = 42.1 SPL
H2 = 77.1 SPL
THD = 0.241%
Can you please share the formula for the calculation?
Thank you
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